Integrand size = 15, antiderivative size = 277 \[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=-\frac {2^{-1-n} e^{i (a-c n)+i (b-d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,\frac {b-d n}{2 d},\frac {1}{2} \left (2+\frac {b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{b-d n}-\frac {2^{-1-n} e^{-i (a+c n)-i (b+d n) x+i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {b+d n}{2 d},1-\frac {b+d n}{2 d},-e^{2 i (c+d x)}\right )}{b+d n} \]
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Time = 0.67 (sec) , antiderivative size = 277, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {4651, 2323, 2285, 2283} \[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=-\frac {2^{-n-1} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (-n,\frac {b-d n}{2 d},\frac {1}{2} \left (\frac {b}{d}-n+2\right ),-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {2^{-n-1} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \operatorname {Hypergeometric2F1}\left (-n,-\frac {b+d n}{2 d},1-\frac {b+d n}{2 d},-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n} \]
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Rule 2283
Rule 2285
Rule 2323
Rule 4651
Rubi steps \begin{align*} \text {integral}& = 2^{-1-n} \int \left (i e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-i e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \, dx \\ & = \left (i 2^{-1-n}\right ) \int e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx-\left (i 2^{-1-n}\right ) \int e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx \\ & = \left (i 2^{-1-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i a-i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (i 2^{-1-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i a+i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx \\ & = -\left (\left (i 2^{-1-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (a-c n)+i (b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\right )+\left (i 2^{-1-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (a+c n)-i (b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx \\ & = -\frac {2^{-1-n} \exp (i (a-c n)+i (b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,\frac {b-d n}{2 d},\frac {1}{2} \left (2+\frac {b}{d}-n\right ),-e^{2 i (c+d x)}\right )}{b-d n}-\frac {2^{-1-n} \exp (-i (a+c n)-i (b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \operatorname {Hypergeometric2F1}\left (-n,-\frac {b+d n}{2 d},1-\frac {b+d n}{2 d},-e^{2 i (c+d x)}\right )}{b+d n} \\ \end{align*}
Time = 2.47 (sec) , antiderivative size = 181, normalized size of antiderivative = 0.65 \[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=-\frac {2^{-1-n} e^{-i (a-c+(b-d) x)} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^{1+n} \left ((b-d n) \operatorname {Hypergeometric2F1}\left (1,\frac {1}{2} \left (2-\frac {b}{d}+n\right ),-\frac {b+d (-2+n)}{2 d},-e^{2 i (c+d x)}\right )+e^{2 i (a+b x)} (b+d n) \operatorname {Hypergeometric2F1}\left (1,\frac {b+d (2+n)}{2 d},\frac {1}{2} \left (2+\frac {b}{d}-n\right ),-e^{2 i (c+d x)}\right )\right )}{(b-d n) (b+d n)} \]
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\[\int \cos \left (d x +c \right )^{n} \sin \left (x b +a \right )d x\]
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\[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right ) \,d x } \]
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Timed out. \[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=\text {Timed out} \]
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\[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right ) \,d x } \]
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\[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=\int { \cos \left (d x + c\right )^{n} \sin \left (b x + a\right ) \,d x } \]
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Timed out. \[ \int \cos ^n(c+d x) \sin (a+b x) \, dx=\int {\cos \left (c+d\,x\right )}^n\,\sin \left (a+b\,x\right ) \,d x \]
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